(3x/4)+(x^2/4)=(1/2)

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Solution for (3x/4)+(x^2/4)=(1/2) equation: 


x in (-oo:+oo)

(x^2)/4+(3*x)/4 = 1/2 // - 1/2

(x^2)/4+(3*x)/4-(1/2) = 0

(x^2)/4+(3*x)/4-1/2 = 0

1/4*x^2+3/4*x-1/2 = 0

DELTA = (3/4)^2-(-1/2*1/4*4)

DELTA = 17/16

DELTA > 0

x = ((17/16)^(1/2)-3/4)/(1/4*2) or x = (-(17/16)^(1/2)-3/4)/(1/4*2)

x = 2*((17/16)^(1/2)-3/4) or x = -2*((17/16)^(1/2)+3/4)

x in { -2*((17/16)^(1/2)+3/4), 2*((17/16)^(1/2)-3/4) }

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